Prove that [ cot square(90 - theta ) /tan square theta - 1 ] + [ cosec square theta / sec square theta -cosec square theta ] = 1 /sin square theta -cos square theta .
Answers
Answered by
0
Answer:
don't know buddyfriends
Similar questions
Environmental Sciences,
4 months ago
Accountancy,
4 months ago
English,
4 months ago
Math,
9 months ago
History,
9 months ago