prove that cot θ+ tan θ= sec θ cosec
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Step-by-step explanation:
IN RHS
cot A+tanA
we can write this as
Cos A ÷SinA +SinA ÷CosA
so,
CosA square + sinA square
1÷sinA * Cos A
Now,
1÷sin A * 1 ÷ cos A
cosecA * secA
hence proved
* this is denoted multiply
square denote the square for theta or any thing in answer
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