Question

Prove that cot $\sf\theta$ - tan $\sf\theta$ =
$\large\sf\ \frac{2 \: {cos}^{2}\theta \: - \: 1}{sin \: \theta \: cos \: \theta} \: = \: \frac{1 \: - \: {sin}^{2} \: \theta}{sin \: \theta \: cos \: \theta}$
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Answer 1

Answer:

Step-by-step explanation:

Answer 2

• refer attachment for detailed answer

note: cos2x = (cos²x - sin²x) = (2cos²x - 1) = (1 - 2sin²x)

there should be 1 - 2sinθ instead 1 - sinθ in your question