Math, asked by insarahul1234, 1 year ago

Prove that (cot theta - cosec theta) ​^2
= 1-cos theta / 1+cos theta

Answers

Answered by yogiraj4
12
Remember these identities. 
csc^2θ = 1/sin^2θ 
cotθ = cosθ/sinθ 

Proving: 
= (cscθ - cotθ)^2 
= csc^2θ - 2cscθcotθ + cot^2θ 
= 1/sin^2θ - 2(1/sinθ)(cosθ/sinθ) + cos^2θ/sin^2θ 
= 1 - 2cosθ + cos^2θ / sin^2θ 
= (1 - cosθ)^2 / (1 - cos^2θ) 
= (1 - cosθ)^2 / (1 + cosθ)(1 - cosθ) 
= (1 - cosθ)/(1 + cosθ) (Verified) 
Hope this will help
Answered by Anonymous
11
⭐️⭐️Hope it helps you⭐️⭐️

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