Question

prove that cot theta-cot 2 theta equal to cosec 2 theta in brainly

Answer 1

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Answer 2

Answers:-

Let

In ∆ABC,right angle at B

Therefore we have

AB^2+BC^2=AC^2

Now dividing the equation by BC^2

We get AB^2/BC^2 + BC^2/BC^2 =AC^2/BC^2

=>{AB/BC}^2 + {BC/BC}^2 ={AC/BC}^2

=>Therefore we get

cot^2A+1=cosec^2A