Prove that :cot theta - tan theta = 2 cos^2 theta-1/sin theta cos theta ...guys please dont answer for the sake of coins ..answer for the sake of helping others...
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LHS =cot 0 -tan 0 ;
writing it in terms of sin and cos we have ;
cos 0/sin 0 - sin 0 /cos 0
cos sq. 0 -sin sq . 0/ sin 0 * cos 0
cos sq A + (- sin sq 0)/sin A cos A
[ by the identity sin sq 0 = cos sq 0=1]
cos sq A =(cos sq A - 1)/sinA cos A
2cos sq A-1 /sin A cos A
=RHS
hence proved
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