Prove that. cot theta +tan theta =cot theta sec squre theta
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Prove cot theta+tan theta=(cosec theta)(sec theta) by completing the following activity:
LHS=cot theta+tan theta
=(cos theta)/(sin theta)+(square)/(cos theta) =(square +square)/(sin thetaxx co cos theta) =(square)/(sin thetaxx cos theta)
=1/(square)xx1/(square)
=cosec thetaxx sec theta
=RHS :. ... ∴cotθ+tanθ=cosecθ×secθ.0
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