prove that cot thita + cosec thita -1 / cot thita - cosec tita +1 = 1 + cos thita / sin thita
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Hey !!!
Solution is in this given attachment !!
_______________________.
Hope it will help you !!!
@Rajukumar111
Solution is in this given attachment !!
_______________________.
Hope it will help you !!!
@Rajukumar111
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Answered by
4
Hii friend,
Cot theta + Cosec theta -1 / Cot theta - Cosec theta +1 = 1+Cos theta/ Sin theta
We have,
LHS = (Cot theta + Cosec theta)-1/(Cot theta - Cosec theta +1)
=> (Cosec theta+ Cot theta)-(Cosec theta-Cot²theta)/(Cot theta - Cosec theta+1)
=> (Cosec theta+Cot theta)[1-(Cot theta-Cot theta)] / (Cot theta-Cosec theta +1)
=> (Cosec theta + Cot theta)(Cot theta-Cosec theta +1) / ( Cot theta - Cosec theta+1)
=> ( Cosec theta+Cot theta)
=> (1/Sin theta + Cos theta/Sin theta)
=> 1+Cos theta/ Sin theta = RHS.
Hence,
LHS = RHS..... PROVED....
HOPE IT WILL HELP YOU...... :-)
Cot theta + Cosec theta -1 / Cot theta - Cosec theta +1 = 1+Cos theta/ Sin theta
We have,
LHS = (Cot theta + Cosec theta)-1/(Cot theta - Cosec theta +1)
=> (Cosec theta+ Cot theta)-(Cosec theta-Cot²theta)/(Cot theta - Cosec theta+1)
=> (Cosec theta+Cot theta)[1-(Cot theta-Cot theta)] / (Cot theta-Cosec theta +1)
=> (Cosec theta + Cot theta)(Cot theta-Cosec theta +1) / ( Cot theta - Cosec theta+1)
=> ( Cosec theta+Cot theta)
=> (1/Sin theta + Cos theta/Sin theta)
=> 1+Cos theta/ Sin theta = RHS.
Hence,
LHS = RHS..... PROVED....
HOPE IT WILL HELP YOU...... :-)
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