prove that cot thita + tan thita = sec thita *cosec thita
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- A trignometic identity
- LHS = RHS
Cot∅+tan∅=sec∅×cosec∅
__________________________
Let break cot and tan
LHS
cos/sin +Sin/cos
=>( sin²+cos²)/sin×cos
we know that sin²+cos²=1
=>1/cos∅.sin∅
=>1/cos∅ × 1/ sin∅
=>cosec∅×sec∅
______________________________
Hence verified LHS =RHS
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