Question

prove that cot²Φ-tan²Φ=cosec²Φ-sec²Φ

Answer 1

L.H.S.= R.H.S. ......,...............

Answer 2

Answer:

$l.h.s. = {cot}^{2}Φ - {tan}^{2} Φ$

$= {cot}^{2} Φ- 1 - {tan}^{2} Φ + 1$

${cot}^{2} Φ - 1 - ( {tan}^{2} Φ - 1)$

$= \cos(ec) {}^{2} Φ - {sec}^{2} Φ$

$= r.h.s.$

L.H.S.=R.H.S.

Hence proved