Math, asked by pritamdube11, 3 months ago

Prove that cot2θ X sec2θ = cot2θ + 1 .
Please I Was Urgent it's Geometry Trigo Questions​

Answers

Answered by Anonymous
10

Step-by-step explanation:

(sec2θ − 1) cot2θ = 1.

(sec2θ − 1) cot2θ = 1.L.H.S. = (sec2 θ – 1) × cot2 θ

(sec2θ − 1) cot2θ = 1.L.H.S. = (sec2 θ – 1) × cot2 θ(using identity 1 + tan2 θ = sec2 θ)

(sec2θ − 1) cot2θ = 1.L.H.S. = (sec2 θ – 1) × cot2 θ(using identity 1 + tan2 θ = sec2 θ)= R.H.S.

(sec2θ − 1) cot2θ = 1.L.H.S. = (sec2 θ – 1) × cot2 θ(using identity 1 + tan2 θ = sec2 θ)= R.H.S.Hence Proved.

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