Prove that cot2θ X sec2θ = cot2θ + 1 .
Please I Was Urgent it's Geometry Trigo Questions
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Step-by-step explanation:
(sec2θ − 1) cot2θ = 1.
(sec2θ − 1) cot2θ = 1.L.H.S. = (sec2 θ – 1) × cot2 θ
(sec2θ − 1) cot2θ = 1.L.H.S. = (sec2 θ – 1) × cot2 θ(using identity 1 + tan2 θ = sec2 θ)
(sec2θ − 1) cot2θ = 1.L.H.S. = (sec2 θ – 1) × cot2 θ(using identity 1 + tan2 θ = sec2 θ)= R.H.S.
(sec2θ − 1) cot2θ = 1.L.H.S. = (sec2 θ – 1) × cot2 θ(using identity 1 + tan2 θ = sec2 θ)= R.H.S.Hence Proved.
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