Question

prove that cot²A -1/sin² A+ 1 = 0​

Answer 1

Step-by-step explanation:

cot²A -1/sin² A+ 1 = 0​

cot²A -cosec² A+ 1 = 0​

-(cosec² A-cot²A)+1 = 0

-1+1 = 0

0 = 0

LHS =RHS

Hence Proved

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Answer 2

Answer:

cot square A = cos sq A/sin sq A

According to the question - cos sq A upon sin sq A - 1 upon sin sq A + 1 = cos sq A -1 + sin sq A upon sin sq A

according to formula ,cos sq A + sin sq A = 1

this implies that 1-1 upon sin sq A gives 0 upon sin sq A = 0

hence proved.