Prove that cotA- cosA/ cotA+ cosA = cosecA- 1/ cosecA+1
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Lhs = (cotA - cosA)/(cotA+cosA)
=(cosA/sinA - cosA)/(cosA/sinA + cosA)
=cosA(1/sinA - 1)/cosA(1/sinA + 1)
= (1/sinA -1)/(1/sinA+1)
=(cosecA-1)/(cosecA+1) since 1/sinA= cosecA
=rhs
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Answered by
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Lhs= cotA-cosA/cotA+cos A
CosA/sin A-cosA/cosA /sin A+cosA
= we take lcm
Then we get
CosA -cosAsinA/sinA/cosA + cosAsinA/sinA
Cut sinA with sinA
So we get cosA-cosAsinA/cosA+cosAsinA
we take common so we get
CosA(1-sinA)/cosA(1+sinA)
Cut cosA with Cos A
1-sinA/ 1+sinA
devide numerator and denominator with sin A
1/sinA-sinA/sinA /1/sinA+ sinA/sinA
(1/sinA = cosecA)
then we get cosecA - 1/cosecA+1
hope it helps you
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