Prove that (cotA-cosA)/(cotA+cosA) = (cosecA-1)/(cosecA+1)
Answers
Answered by
548
lhs = (cotA - cosA)/(cotA+cosA)
=(cosA/sinA - cosA)/(cosA/sinA + cosA)
=cosA(1/sinA - 1)/cosA(1/sinA + 1)
= (1/sinA -1)/(1/sinA+1)
=(cosecA-1)/(cosecA+1) since 1/sinA= cosecA
=rhs
=(cosA/sinA - cosA)/(cosA/sinA + cosA)
=cosA(1/sinA - 1)/cosA(1/sinA + 1)
= (1/sinA -1)/(1/sinA+1)
=(cosecA-1)/(cosecA+1) since 1/sinA= cosecA
=rhs
Answered by
438
Hi there ♥️
=RHS
Hence proved ✅✅
Thanks :)
=RHS
Hence proved ✅✅
Thanks :)
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