prove that (cotA+tan B)÷(cotB+tanA)=cotA×tanB
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The proof is in the attachment
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Dhrupad12:
thnks
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Just put numbers in
(Cot 30 + tan 45):(cot 45 + tan 30)=cot 30 x tan 45
(√3 + √3) : (1/√3 + 1/√3) = √3 x √3
2√3 : 1/2√3 =3
√3 x √3 = 3
(Cot 30 + tan 45):(cot 45 + tan 30)=cot 30 x tan 45
(√3 + √3) : (1/√3 + 1/√3) = √3 x √3
2√3 : 1/2√3 =3
√3 x √3 = 3
Cot is 1/tan so..
Sorry 45 should be 60
thnks
Np
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