Prove that cp = ab
Plz be quick to prove ..........
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divyani0:
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☺️
Here,
ar∆ABC = ½×AC×BC = ½×b×a ...... (i)
also,
ar∆BAC = ½×CD×AB = ½×p×c ...... (ii)
equating both eqⁿ, we get
½×AC×BC = ½×CD×AB
=> ½×b×a = ½×p×c
=> ba = cp
Hence proved!..(^-^)...
☺️
Here,
ar∆ABC = ½×AC×BC = ½×b×a ...... (i)
also,
ar∆BAC = ½×CD×AB = ½×p×c ...... (ii)
equating both eqⁿ, we get
½×AC×BC = ½×CD×AB
=> ½×b×a = ½×p×c
=> ba = cp
Hence proved!..(^-^)...
☺️
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