Math, asked by ak005lee, 1 year ago

prove that cube of any positive integer is in the of 4m,4m+2,4m+3 for integer m​

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Answered by divya1211
1

i hope so it will be help ful for u .

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Answered by Anonymous
0

According to euclid's division lemma

a=bq+r so b=4

Let n be positive integer. Then it forms 4q ,4q+1

  1. (4q)^3 =4(16q)^3 = 4m, where m=16q^3.
  2. (4q+1)^3 =64q^3+48 a^2 +12q+1

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