Prove that cube root of 11 is iraational.
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Answers
Step-by-step explanation:
Let as assume that √11 is a rational number.
A rational number can be written in the form of p/q where q ≠ 0 and p , q are non negative number.
√11 = p/q ....( Where p and q are co prime number )
Squaring both side !
11 = p²/q²
11 q² = p² ......( i )
p² is divisible by 11
p will also divisible by 11
Let p = 11 m ( Where m is any positive integer )
Squaring both side
p² = 121m²
Putting in ( i )
11 q² = 121m²
q² = 11 m²
q² is divisible by 11
q will also divisible by 11
Since p and q both are divisible by same number 11
So, they are not co - prime .
√11 is an irrational number
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Answer:
Sal proves that the square root of any prime number must be an irrational number. For example, because of this proof we can quickly determine that √3, √5, √7, or √11 are irrational numbers.
Step-by-step explanation: