Prove that cube root of 2 is an irrational numbers
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Answered by
66
use cubrt(2) to mean cube root of 2
Let cubrt(2) = a/b which is in simplest form (no common factors except 1)
Then 2 = (a^3)/(b^3)
then 2(b^3) = a^3
This means a^3 is even. This means a is even.
Let a = 2k. So a^3 = 8k^3
This means 2(b^3) = 8k^3
then b^3 = 4k^3
This means b^3 is even. This means b is even
This implies both a and b are even.
But this is impossible because a/b is in simplest form
Therefore cubrt(2) is irrational
I hope this help you
Let cubrt(2) = a/b which is in simplest form (no common factors except 1)
Then 2 = (a^3)/(b^3)
then 2(b^3) = a^3
This means a^3 is even. This means a is even.
Let a = 2k. So a^3 = 8k^3
This means 2(b^3) = 8k^3
then b^3 = 4k^3
This means b^3 is even. This means b is even
This implies both a and b are even.
But this is impossible because a/b is in simplest form
Therefore cubrt(2) is irrational
I hope this help you
Answered by
15
Step-by-step explanation:
2=(a^3)/(b^3)
then 2*b^3)=a^3
means a^3iseven
a=2k
so.b^3=4k^3
means b^3 is even
then b is even
it mean a and b both are even
it is not possible because a and b is in simplest form
proved ube root 2 is irrational
hope u understand.
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