prove that cube root of 7 is irrational
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because it cannot be factorise
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Answered by
2
Hey there. The answer for your question is:
It can be proved because cube root of 7 is 1.92.
It is because 1.92 * 1.92 * 1.92 = 7.077888.
And hence it is proven that 1.92 is the cube root of 7 and it is an irrational number.
Hope this answer helps you. If it helped you then don't forget to mark it as a brainliest answer or at least give me a thanks. Please. Thank you for your cooperation my friend.
It can be proved because cube root of 7 is 1.92.
It is because 1.92 * 1.92 * 1.92 = 7.077888.
And hence it is proven that 1.92 is the cube root of 7 and it is an irrational number.
Hope this answer helps you. If it helped you then don't forget to mark it as a brainliest answer or at least give me a thanks. Please. Thank you for your cooperation my friend.
Answered by
1
Assume that cube rt 7 is rational.
Then (7)^(1/3) = a/b where a and b are integers and a/b is reduced to lowest terms.
Then a=b[7^(1/3)]
Since a is a multiple of b and a is an integer, b divides a.
Since b divides a, a = nb and n is an integer.
Therefore 7^(1/3) = a/b = nb/b, so a/b is not reduced to lowest terms.
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