Math, asked by Anonymous, 1 year ago

prove that cube root of 7 is irrational
fast plssssssssssssssssssssssssssssssssss
don't copy from google or meritnation pls I will give them 50 points


saaaaaaaa: because it cannot be factorise
Anonymous: but prove it

Answers

Answered by theuniverseboss
2
Hey there. The answer for your question is:

It can be proved because cube root of 7 is 1.92.
It is because 1.92 * 1.92 * 1.92 = 7.077888.

And hence it is proven that 1.92 is the cube root of 7 and it is an irrational number.

Hope this answer helps you. If it helped you then don't forget to mark it as a brainliest answer or at least give me a thanks. Please. Thank you for your cooperation my friend.

Anonymous: real numbers chapter
Answered by anitadas408
1

Assume that cube rt 7 is rational.

Then (7)^(1/3) = a/b where a and b are integers and a/b is reduced to lowest terms.

Then a=b[7^(1/3)]

Since a is a multiple of b and a is an integer, b divides a.

Since b divides a, a = nb and n is an integer.

Therefore 7^(1/3) = a/b = nb/b, so a/b is not reduced to lowest terms.

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