Math, asked by kavitaramsinghani545, 11 months ago

prove that cyclic Parallelogram is a rectangle​

Answers

Answered by kabadeindu
2

Answer:

Given,

ABCDABCD is a cyclic parallelogram.

To prove,

ABCDABCD is a rectangle.

Proof:

∠1 + ∠2 = 180°∠1+∠2=180° ...Opposite angles of a cyclic parallelogram

Also, Opposite angles of a cyclic parallelogram are equal.

Thus,

∠1 = ∠2∠1=∠2

= ∠1 + ∠1 = 180°⇒∠1+∠1=180°

= ∠1 = 90°⇒∠1=90°

One of the interior angle of the parallelogram is right angled. Thus,

ABCDABCD is a rectangle.

Hope it helps....!!!

Answered by ArushSrivastavaHUM
2

Answer:

angle A= angle C( opp angle of IIgm are equal)

Also,

angle A +angle C is 180 (sum of opp angle of a cyclic IIgm)

=> 2 angle A = 180

=> angle A =90

Now, In a IIgm one angle is 90

therefore, it is a rectangle

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