prove that cyclic Parallelogram is a rectangle
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Answered by
2
Answer:
Given,
ABCDABCD is a cyclic parallelogram.
To prove,
ABCDABCD is a rectangle.
Proof:
∠1 + ∠2 = 180°∠1+∠2=180° ...Opposite angles of a cyclic parallelogram
Also, Opposite angles of a cyclic parallelogram are equal.
Thus,
∠1 = ∠2∠1=∠2
= ∠1 + ∠1 = 180°⇒∠1+∠1=180°
= ∠1 = 90°⇒∠1=90°
One of the interior angle of the parallelogram is right angled. Thus,
ABCDABCD is a rectangle.
Hope it helps....!!!
Answered by
2
Answer:
angle A= angle C( opp angle of IIgm are equal)
Also,
angle A +angle C is 180 (sum of opp angle of a cyclic IIgm)
=> 2 angle A = 180
=> angle A =90
Now, In a IIgm one angle is 90
therefore, it is a rectangle
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