Question

prove that cyclic parallelogram is a rectangle​

Answer 1

Answer:

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Answer 2

Answer:

keep patience , here is your answer

so, there are many ways to solve this but I m going to give you one of the easiest

Given -: ABCD is a cyclic parallelogram

so ,

In triangle ADB and triangle BCD

AB=CD( oppositesidesofparallelogram )

AD=BC (oppositesides ofparallelogram )

DB=BD (oppositesides ofparallelogram )

by using S.S.S CRITERION ∆ADB=~∆BCD

So, angle A = angle C ( by cpct )

and , since the sum of opposite angle of a cyclic quadrilateral is 180°

it means , angle A + Angle C = 180°

2(Angle A) = 180° ( angleA = angle C)

Angle A = 90°

similarly , angle c is also of 90°

then , by this we get that cyclic parallelogram is a rectangle

Hence proved