Prove that cyclic parallelogram is always a rectangle.
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3
in a cyclic quadrilateral, opp angles are supplementary
in a parallelogram, opp angles are equal
⇒x+x=180
⇒x=90
and opp sides are equal
⇒the parallelogram is a rectangle
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Given, that ABCD is a parallelogram
∠A = ∠C
∠B = ∠D
To find, ABCD is a rectangle
Solution :- ABCD is a cyclic parallelogram
Cyclic parallelogram measures upto 180°
∠A + ∠C = 180°
∠B + ∠D = 180°
∠B + ∠B = 180°
2m∠B = 180°
m∠B =
m∠B = 90°
If, m∠B = 90° then m∠D = 90°
Opposite angles of rectangle are congruent
If, m∠A = m∠C
and m∠A = 90°
So, m∠C = 90°
∴ ABCD is a rectangle as all sides measures 90°
∠A = ∠C
∠B = ∠D
To find, ABCD is a rectangle
Solution :- ABCD is a cyclic parallelogram
Cyclic parallelogram measures upto 180°
∠A + ∠C = 180°
∠B + ∠D = 180°
∠B + ∠B = 180°
2m∠B = 180°
m∠B =
m∠B = 90°
If, m∠B = 90° then m∠D = 90°
Opposite angles of rectangle are congruent
If, m∠A = m∠C
and m∠A = 90°
So, m∠C = 90°
∴ ABCD is a rectangle as all sides measures 90°
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