Question

Prove that Diagonal of a parallelogram divides it into two congruent triangle?
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Answer 1

Step-by-step explanation:

In parallelogram ABCD,

Angle A = Angle C .......(since opp. angles of a llgm are equal) .....1

Similarly , Angle B = Angle D

Construct a diagnal BD

Now , angle ABD = angle BDC ...(diagnols bisect the angles of a llgm).....2

Side AD = side BC....(opp. sides of llgm are equal)..3

From 1, 2, 3

By ASA congruency rule

triangle ABD = triangle BDC

. HENCE PROVED

Answer 2

Answer:

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