Question

prove that diagonal of a parallelograms divides it into two congruent triangles​

Answer 1

Step-by-step explanation:

We have two trinagles when the diagonal cuts the parallelogram

to prove that these two triangles are congruent

First, the opposite angles of the parallelogram are equal

Second, the long adjacent sides are equal

Third, short adjacent sides are equal

By SAS the two triangles are congruent

Answer 2

Hey Mate,

Here is your answer

Given: A parallelogram ABCD and AC is its diagonal .

To prove : △ABC ≅ △CDA

Proof : In △ABC and △CDA, we have  

∠DAC =  ∠BCA [alt. int. angles, since AD | | BC]  

AC = AC [common side]  

and ∠BAC =  ∠DAC [alt. int. angles, since AB | | DC]  

∴ By ASA congruence axiom, we have  

△ABC ≅ △CDA

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Hope it helps.......Brainliest Pls