Prove that diagonal of a rectangle or parallelogram divides it into two congruent triangles. (Hint: Opposite sides of a rectangle are equall.
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Step-by-step explanation:
Let the number be X
formula= a-b= a-2a+b
Do with this formula you will complete
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Step-by-step explanation:
- Consider ABCD is a parallelogram which is divided by a diagonal in two equal parts. The parallelogram is in two parts which are triangle ADB and CDB. As opposite sides of parallelogram are parallel and equal so all the sides of triangle ADB and CDB are equal so the triangle ADB and CDB are congruent.
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