Question

Prove that diagonal of a rhombus bisect each other and perpendicular to each other.​

Answer 1

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Proof . – Let ABCD be a rhombus whose diagonal AC and BD intersect at the point O.

We know that the diagonals of a parallelogram bisect each other.

Also we know that every rhombus is a parallelogram.

Therefore OA=OC and OB=OD.

From triangle(COB) and triangle (COD), we have:

CB=CD sides of rhombus.

CO=CO. Common

OB=OD proved

Therefore tri(COB)~tri(COD) by SSS congruence.

=> But Thus, Hence, the diagonals of a rhombus bisect each other at right angles.

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Answer 2

A rhombus is a parallelogarm , so we will use what we already know about parallelogarms -that the diagonals bisect each other . it is then easy to show that the triangles ∆AOD and ∆ AOB are congruent using theSide- Side -Side postulate , and from that <AOD =< AOB . ..

Step-by-step explanation:

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