Question

Prove that diagonal of rhombus bisect each other at right angle?

Answer 1

☆Hello friend☆
Lets take a rhombus: □ABCD.
GIVEN: ABCD is a rhombus
To proove: Diagnols bisect at 90°
PROOF
Take triangles AOB and BOC
OB=OB( Common)
AB= BC( Given)
AO=OC( BD bisect AC equally)
Hence triangle are congurent.
Angle AOB=BOC=(c.p.c.t)
AOB+AOB=180°
2AOB=180°
AOB= 180°/2= 90°
$hope \: it \: helps$
☺☺☺

Answer 2

I hope it will help you