prove that diagonals bisect the parallelogram
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Given,
In tri.(ADB)
AO=OA (common)
AD=AB
angle A(common)
hence by (sas rule) tri.(AOD) AND TR.(AOB) ARE CONGRUENT
HENCE BY (C.P.C.T)
AO=OC=OB=OD
In tri.(ADB)
AO=OA (common)
AD=AB
angle A(common)
hence by (sas rule) tri.(AOD) AND TR.(AOB) ARE CONGRUENT
HENCE BY (C.P.C.T)
AO=OC=OB=OD
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