Question

prove that diagonals of a parallelogram divides into two triangles is equal areas

Answer 1

let parallelogram be ABCD
to prove trABD~=trBCD
IN tr ABD &trBCD
BD=BD(comman)
angleA=angleC (opposite angles of a parallelogram)
angleDBC=angleADB(AB parallel to DC &DB is transversal so angleB &angle D are corresponding angles)
by ASA congruency criteria
trADB~=trBCD