Question

prove that diagonals of a rhombus bisect each other at right angles​

Answer 1

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Lets take a rhombus: □ABCD.

GIVEN: ABCD is a rhombus

To proove: Diagnols bisect at 90°

PROOF

Take triangles AOB and BOC

OB=OB( Common)

AB= BC( Given)

AO=OC( BD bisect AC equally)

Hence triangle are congurent.

Angle AOB=BOC=(c.p.c.t)

AOB+AOB=180°

2AOB=180°

AOB= 180°/2= 90°