prove that diagonals of a square are equal and bisect each other at right angles
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Step-by-step explanation:
w. k. t.,,
consider a squre ABCD of diagonals AC and BD
all the sides in the square are equal
let side of square be "a"
by pythogoras thm lenght of diagonals i. e. AC=BD=a√2
(√a^2+√a^2=a√2)
by this it is clear that both the diagonals are equal
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