Math, asked by Sumitamishra, 11 months ago

prove that diagonals of parallelogram bisect each other​

Answers

Answered by Awiskangreat
0

Answer:

Step-by-step explanation:

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Answered by JanviMalhan
89

Step-by-step explanation:

Let consider a parallelogram ABCD in which AB||CD and AD||BC.

In ∆AOB and ∆COD , we have

∠DCO=∠OAB (ALTERNATE ANGLE)

∠CDO= ∠OBA. (ALTERNATE ANGLE)

AB=CD. (OPPOSITE SIDES OF ||gram)

therefore , ∆ AOB ≅ ∆COD. (ASA congruency)

hence , AO=OC and BO= OD. (C.P.C.T)

  \huge \rm{ hence \: proved}

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