Math, asked by pankhudi33, 1 year ago

prove that diagonals of parallelogram divides it into two congruent triangles

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Answered by Arrush

Step-by-step explanation:

Let ABCD be the Parallelogram

AC is its one diagonal

To prove: Diagonal of a parallelogram divides it into two equal traiangles

In ΔABC and ΔCDA

AB=CD (opposite sided of a ||gram)

BC=AD (opposite sides of a ||gram)

AC=AC (common)

hence, ΔABC≅ΔCDA (by SSS)

Hence, proved

Similarly it can be done for other two triangles formed by the other diagonal...

Mark this as the Brainliest if this helps

pankhudi33: can y pls show me fig.

Answered by sharmapranay1234

Answer:

Step-by-step explanation:

Refer to the image

It may help

Attachments:

pankhudi33: sorry not understanding your handwriting

sharmapranay1234: Let ABCD be a parallelogram two Triangles are abd and bdc... angle 1 is equal to angle 2... (alternate angles) angle C is equal to angle a (opposite angles) ab is equal to CD opposite sides of a parallelogram similarly Ad is equal to Bc

sharmapranay1234: Use any congruency criteria

pankhudi33: okay thanks

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prove that diagonals of parallelogram divides it into two congruent triangles