Question

prove that diagonals of rectangle bisect each other and equal​

Answer 1

Step-by-step explanation:

rectangle ABCD, diagonals bisect the angles. Consider ΔAOD and ΔBOC AD = BC (ABCD is a rectangle) ∠AOD = ∠BOC (Vertically opposite angles) ∠OAD = ∠OCB = 45° (Diagonals bisect the angles) ΔAOD ≅ ΔBOC (AAS congruence criterion) Therefore, OA = OC and OB = OD Thus the diagonals bisect each other in a rectangle.