Question

prove that diameter is the longest chord of the circle
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Answer 1

Step-by-step explanation:

COD is the line which connects two points in the circle and and that line will not pass through the centre of the circle .

Paris diameter line joining two points on the circumference of the circle which passes through the centre the centre position of the circle that is when we divide the circle into two equal halves we get a semicircle in which the base that is the diameter of that will be the longest line and therefore it is the longest chord

Answer 2

Answer:

Step-by-step explanation:

Take any chord in a circle, say with endpoints AB. Let O be the center of the circle. Then segments AO and BO are radii of the circle. AOB is a triangle, and we know that the sum of the lengths of two sides of a triangle is always greater than or equal to the length of the third side. So:

|AB| ? |AO| + |BO|

 

(Here |AB| means length of AB.)

 

So, the maximum length of the chord AB can be equal to |AO| + |BO|. Now AO and BO are the radii of the circle, hence |AO| + |BO| = 2r = d (diamter of the circle). 

 

So, maximum length of the chord AB = |AO| + |BO| = d

Hence diameter of the circle represents the longest chord in the circle.

Hope it help you ..