prove that difference of any two sides of triangle is less than its third side
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2
let side a.=4 ,side b=5,side
c=6
so when we substract 5 from 6 then diff. will be 1
c=6
so when we substract 5 from 6 then diff. will be 1
Answered by
6
Hey mate,
ANSWER---»»
FIRST. LET THE ONE SIDE = 8
SECOND SIDE =9
WHEREAS THE THIRD SIDE = 10
THEREFORE WHEN WE SUBRACT IT
WE WILL GET =( SECOND SIDE - THIRD SIDE)
=(9-10)
=1
HOPE IT WILL HELP YOU.❤❤❤
ANSWER---»»
FIRST. LET THE ONE SIDE = 8
SECOND SIDE =9
WHEREAS THE THIRD SIDE = 10
THEREFORE WHEN WE SUBRACT IT
WE WILL GET =( SECOND SIDE - THIRD SIDE)
=(9-10)
=1
HOPE IT WILL HELP YOU.❤❤❤
guptaneema02p9qt5k:
thanks
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