prove that difference og two sides of a triangle is lesser than the third side
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Let us take a triangle ABC with
Side A = 3cm
Side B = 4cm
Side C = 5cm
Now, B - A cm
4 - 3 = 1 cm
1cm is lesser than 5 cm.
B-A < C
Thus it proves that the difference of two sides is lesser than the third side.
Side A = 3cm
Side B = 4cm
Side C = 5cm
Now, B - A cm
4 - 3 = 1 cm
1cm is lesser than 5 cm.
B-A < C
Thus it proves that the difference of two sides is lesser than the third side.
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