Question

Prove that E is midpoint of AC
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Answer 1

Given ABC is a right angled triangle in which angle B =90°

and, AB=AC

BE is perpendicular on AC

So, AEB=CEB=90°

Comparing triangle ABE and CBE

AB=BC[Given]

AEB=CEB=90°

BE=BE[common side]

So,

triangle ABE is congruence triangle CBE

Therefore,

AE=EC[CPCT]

Thus, it is proved that E the mid point of AC.

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