Prove that each diagonal of a rhombus bisects the angle through which it passes
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Let, ABCD be a rombus and the vertex where their diagonal intersect be 'O'
Then in triangle AOD and DOC
As;
AD = DC
OD = OD
angle AOC = AOD
So triangle AOD = DOC
As angle AOD = DOC
and AOD + DOC = 180
2 AOD = 180
AOD = 90
So as opposite angles are equal when two lines intersect so all four angles are 90°
Then in triangle AOD and DOC
As;
AD = DC
OD = OD
angle AOC = AOD
So triangle AOD = DOC
As angle AOD = DOC
and AOD + DOC = 180
2 AOD = 180
AOD = 90
So as opposite angles are equal when two lines intersect so all four angles are 90°
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