prove that each of the following equation has only one solution.find the solution
Answers
Answer:
Simplifying
4y2 + -28y + 49 = 0
Reorder the terms:
49 + -28y + 4y2 = 0
Solving
49 + -28y + 4y2 = 0
Solving for variable 'y'.
Factor a trinomial.
(7 + -2y)(7 + -2y) = 0
Subproblem 1
Set the factor '(7 + -2y)' equal to zero and attempt to solve:
Simplifying
7 + -2y = 0
Solving
7 + -2y = 0
Move all terms containing y to the left, all other terms to the right.
Add '-7' to each side of the equation.
7 + -7 + -2y = 0 + -7
Combine like terms: 7 + -7 = 0
0 + -2y = 0 + -7
-2y = 0 + -7
Combine like terms: 0 + -7 = -7
-2y = -7
Divide each side by '-2'.
y = 3.5
Simplifying
y = 3.5
Subproblem 2
Set the factor '(7 + -2y)' equal to zero and attempt to solve:
Simplifying
7 + -2y = 0
Solving
7 + -2y = 0
Move all terms containing y to the left, all other terms to the right.
Add '-7' to each side of the equation.
7 + -7 + -2y = 0 + -7
Combine like terms: 7 + -7 = 0
0 + -2y = 0 + -7
-2y = 0 + -7
Combine like terms: 0 + -7 = -7
-2y = -7
Divide each side by '-2'.
y = 3.5
Simplifying
y = 3.5
Answer:
4y² - 28y + 49 = 0
(2y)² - 28y + 7² = 0
a² - 2ab + b² = (2y)² - 2 × 2y × 7 + 7²