Question

Prove that each of the following equation has only one solution. Find the solution. 4y² - 28y + 49 = 0​

Answer 1

Answer:

x = 7/2; proved

Step-by-step explanation:

Given 4y² - 28y + 49 = 0

To prove:- given equation has only one solution

Sol:-

=> 4y² - 14y - 14y + 49 = 0

=> 2y(2y - 7) - 7(2y - 7) = 0

=> (2y - 7)² = 0

=> 2y - 7 = 0

=> 2y = 7

=> y = 7/2

Since given quadratic equation has two same root

=> the given equation has only one solution