Math, asked by shashika7142, 7 months ago

Prove that each of the following equations has one sol find 4y^2-28y+49=0

Answers

Answered by kumarianshika310
1

Answer:

Simplifying

4y2 + -28y + 49 = 0

Reorder the terms:

49 + -28y + 4y2 = 0

Solving

49 + -28y + 4y2 = 0

Solving for variable 'y'.

Factor a trinomial.

(7 + -2y)(7 + -2y) = 0

Subproblem 1

Set the factor '(7 + -2y)' equal to zero and attempt to solve:

Simplifying

7 + -2y = 0

Solving

7 + -2y = 0

move all terms containing y to the left, all other terms to the right.

Add '-7' to each side of the equation.

7 + -7 + -2y = 0 + -7

combine like terms: 7 + -7 = 0

0 + -2y = 0 + -7

-2y = 0 + -7

Combine like terms: 0 + -7 = -7

-2y = -7

Divide each side by '-2'.

y = 3.5

Simplifying

y = 3.5

Subproblem 2

Set the factor '(7 + -2y)' equal to zero and attempt to solve:

Simplifying

7 + -2y = 0

Solving

7 + -2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-7' to each side of the equation.

7 + -7 + -2y = 0 + -7

Combine like terms: 7 + -7 = 0

0 + -2y = 0 + -7

-2y = 0 + -7

Combine like terms: 0 + -7 = -7

-2y = -7

Divide each side by '-2'.

y = 3.5

Simplifying

y = 3.5

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