prove that each set of co-ordinate are the vertices of parallelogram
(5,-3) (1,-11) (7,-6) (1,2)
please help me....
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hi mate here is ur answer
A(5,-3), B ( 1,-11) C(7,6) AND D (1,2)
USING DISTANCE FORMULAE
find the distance of AB ,BC,CD,DA ,AC, DB
THE DISTANCE OF AB
√(5-1)^2 + (-3-(-11))^2
=√(4)^2+ (8)^2
=√16+64
=√80
THE DISTANCE OF BC
SIMILARLY FIND THE DISTANCE
=√61
THE DISTANCE OF CD
=√100
THE DISTANCE OF DA
=√41
THE DISTANCE OF AC
=√13
THE DISTANCE OF DB
= √81
THESE ARE NOT THE VERICES OF A PARALLELOGRAM BECAUSE OPPOSITE SIDES ARE NOT EQUAL AND DIAGNOLS ARE ALSO NOT EQUAL
HOPE IT HELPS!!!
ashfaanjum:
can you please help me with some more questions
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