Question

Prove that ED bisects BC
given, BE = AB
& ABCD is a parallelogram​

Answer 1

ANSWER :

Consider triangle BOE and COD

AB=CD(Opposite sides of parallelogram)

BUT AB=BE

SO CD=BE........ (1)

COD=BOE(Vertically opp. Angles)..... (2)

DCO=EBO(Alternate interior angles)

.... (3)

From (1),(2),(3),

By AAS, Triangle BOE is congruent to triangle COD

So,

BO=CO (CPCT)

ie, ED bisects BC

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