Prove that elastic energy density is equal to 1/2 × stress × strain.
with proper derivation
Answers
Explanation:
Let the wire be of unstretched length L and let a force F produce an extension e. (Assume that the elastic limit of the wire has not been exceeded and that no energy is lost as heat.)
Consider Figure 1(a). The work done a the force is Fs but in this case the force varies from 0 at the start to F at the end when the wire is stretched by an amount e. Therefore:
Work done on the wire during stretching = average force x extension = ½ Fe
But the work done by F is equal to the energy gained by the wire.
Therefore:
work done = average force x extension = ½ Fe
Therefore:
work done = energy stored = ½ Fe = ½ EAe2/L
And this energy is the shaded area of the graph.
If the extension is increased from e1 to e2 then the extra energy stored is given by:
Energy stored = ½ F[e2 – e1] = ½ EA[e22 – e12]/L
This is the shaded area on the graph in Figure 1(b), and in general the energy stored in an extension is the area below the line in the force-extension graph. It can also be shown that:
Energy stored per unit volume of a specimen = ½ stress x strain