Physics, asked by dipak1544, 1 year ago

Prove that electric dipole moment of a nucleus in its ground state vanishes

Answers

Answered by ap1782
1

Answer:

The nuclear magnetic moment is the magnetic moment of an atomic nucleus and arises from the spin of the protons and neutrons. It is mainly a magnetic dipole moment; the quadrupole moment does cause some small shifts in the hyperfine structure as well. All nuclei that have nonzero spin also possess a nonzero magnetic moment and vice versa, although the connection between the two quantities is not straightforward or easy to calculate.

The nuclear magnetic moment varies from isotope to isotope of an element. For a nucleus of which the numbers of protons and of neutrons are both even in its ground state (i.e. lowest energy state), the nuclear spin and magnetic moment are both always zero. In cases with odd numbers of either or both protons and neutrons, the nucleus often has nonzero spin and magnetic moment. The nuclear magnetic moment is not sum of nucleon magnetic moments, this property being assigned to the tensorial character of the nuclear force, such as in the case of the most simple nucleus where both proton and neutron appear, namely deuterium nucleus, deuteron.

Answered by IonicYadav
0

Answer:

Until yesterday I thought they have. Googling a little bit around the measured values, I've found nothing.

As I've heard on the chat, the nuclei don't have an EDM. Although it would be possible by the symmetry violations of the weak interaction, it doesn't happen.

But I am asking not for the EDM due to weak asymmetry. I am asking for the lack of the EDM due to the asymmetric charge distribution in them.

Nuclei have a lot of elementary particles, interacting in quite complex ways (strong, EM and weakly). Why should the charges be distributed in them always to a 0 EDM? What is the mechanism, or what is the reason, to zero out any EDM in them?

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