Question

prove that electrostatic field at surface of a charged conductor is E=sigma/epsilon

Answer 1

Answer:

Here (sigma) is surface charge density (C/m^2) and (epsilon zero) is permittivity of free space. A spherical charged conductor has surface charge density sigma. The electric field on its surface is E. If the radius of the sphere is doubled keeping the surface charge density unchanged.

Answer 2

Answer:

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Explanation:

So that tangent on charged conductor gives the direction of the electric field at that point.