Question

prove that energy remains constant in case of freely falling body​

Answer 1

Answer:

In the case of a freely falling body, it is the mechanical energy of the system that is conserved. Mechanical energy (E) is the sum of the potential energy (U) and the kinetic energy (K) of the freely falling body. Therefore, E=K+U=constant.

Explanation:

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Answer 2

Answer:

In the case of a freely falling body, it is the

mechanical energy of the system that is

conserved. Mechanical energy (E) is the sum

the potential energy (U) and the kinetic energy

(K) of the freely falling body. Therefore,

E=K+U=constant.

Explanation:

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