Question

prove that equal chords of a circle substance equal angle at the centre...​

Answer 1

Proof: Given, in ∆AOB and ∆POQ,

AB = PQ (Equal Chords) …………..(1)

OA = OB= OP=OQ (Radii of the circle) ……..(2)

From eq 1 and 2, we get;

∆AOB ≅ ∆POQ (SSS Axiom of congruency)

Therefore, by CPCT (congruent parts of congruent triangles), we get;

∠AOB = ∠POQ

Hence, Proved.

Answer 2

hope it helps............